The angular momentum of an electron in Bohr's hydrogen atom whose energy is $- 3.4 e V$ , is
$\frac{5 h}{2 π}$
$\frac{h}{π}$
$\frac{2 h}{3 π}$
$\frac{h}{2 π}$

Question

The angular momentum of an electron in Bohr-s hydrogen atom whose energy is -3-4 eV- isdfrac-5h-2 pi-dfrac-h-pi-dfrac-2h-3 pi-dfrac-h-2 pi-

Toppr Admin · Accepted Answer

Energy of electron in nth orbit of hydrogen atomEn-x2212-13-6n2eV-x21D2-3-4-x2212-13-6n2-x21D2-n2-4or- n-2Angular momentum of electron-L-nh2-x3C0-2h2-x3C0-h-x3C0-

The angular momentum of an electron in Bohr's hydrogen atom whose energy is −3.4eV, is5h2πhπ2h3πh2π

Energy of electron in nth orbit of hydrogen atomEn=−13.6n2eV⇒3.4=−13.6n2⇒n2=4or, n=2Angular momentum of electron,L=nh2π=2h2π=hπ

The angular momentum of an electron in Bohr's hydrogen atom whose energy is $- 3.4 e V$ , is
$\frac{5 h}{2 π}$
$\frac{h}{π}$
$\frac{2 h}{3 π}$
$\frac{h}{2 π}$

Energy of electron in nth orbit of hydrogen atom
$E_{n} = - \frac{13.6}{n^{2}} e V$
$\Rightarrow 3.4 = - \frac{13.6}{n^{2}} \Rightarrow n^{2} = 4$
or, $n = 2$
Angular momentum of electron,
$L = \frac{n h}{2 π} = \frac{2 h}{2 π} = \frac{h}{π}$