Question

The area of a metallic plate is $$ 10^{-2} m^2 $$. A charge of $$ 10 \mu C $$ is given to the plate. Determine the electric filed intensity at a point near to the plate.

Answer 1

Given $$ A = 10^{-2} m^2 $$

$$ q = 10 \mu C = 10 \times 10^{-6} C $$

Electric field intensity near plate

$$ E = \frac { \sigma}{ 2 \epsilon_0 } $$

Where $$ \sigma $$ is surface charge density.

$$ \sigma = \frac {q}{A} $$

$$ \therefore \quad E = \frac {q}{ 2 \epsilon_0A} $$

$$ = \frac { 10 \times 10^{-6} }{ 2 \times 8.86 \times 10^{-12} \times 10^{-2} } $$

$$ = \frac {10^{-5} \times 10^{14} } {17.72} $$

$$ = 5.65 \times 10^7 V/m $$