Question

The area of a rectangular courtyard is $(10x^3-11x^2+19x+10)$ sq units. If one of its sides is $(2x^2-3x+5)$ units, then the other side is

• A. $(5x+2)$ units
• B. $-5x+2$
• C. $-(5x+2)$ units
• D. $5x-2$

Answer 1

Answer: (A)

Given, area of a rectangular courtyard $=(10x^3-11x^2+19x+10)$sq. units.

One side $=(2x^2-3x+5)$

Let the other side of the rectangle be $y$ cm

Area of a rectangle $=$ length $\times$ breath

$\Rightarrow (10x^3-11x^2+19x+10)=(2x^2-3x+5)y$

$\Rightarrow y=\frac{10x^3-11x^2+19x+10}{2x^2-3x+5}$

	$5x+2$
$2x^2-3x+5$	$10x^3-11x^2+19x+10$
	$10x^3-15x^2+25x$
	$4x^2-6x+10$ $4x^2-6x+10$
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