The area of a trapezium with height 14-cm is 504-cm-2- If the parallel sides are in the ratio 4-colon-5- their lengths-30-cm-42-cm-32-cm-40-cm-32-cm-42-cm-30-cm-40-cm-

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Area of trapezium-12-sum of parallel opposite side-height-Let parallel side are 4x-5x504-12-4x-5x-14-504-2-9-14-xx-8side of one side-4-8-32cm-5-8-40cm

The area of a trapezium with height $14 c m$ is $504 c m^{2}$ . If the parallel sides are in the ratio $4 : 5$ , find their lengths.
$30 c m, 42 c m$ .
$32 c m, 40 c m$ .
$32 c m, 42 c m$ .
$30 c m, 40 c m$ .

Area of trapezium $= \frac{1}{2}$ (sum of parallel opposite side)(height)
Let parallel side are $4 x, 5 x$
$504 = \frac{1}{2} (4 x + 5 x) (14)$
$\frac{(504) (2)}{9 (14)} = x$
$x = 8$
side of one side $= 4 (8) = 32 c m, 5 (8) = 40 c m$

The area of a trapezium with height 14cm is 504cm2. If the parallel sides are in the ratio 4:5, find their lengths.30cm,42cm.32cm,40cm.32cm,42cm.30cm,40cm.

Area of trapezium=12(sum of parallel opposite side)(height)Let parallel side are 4x,5x504=12(4x+5x)(14)(504)(2)9(14)=xx=8side of one side=4(8)=32cm,5(8)=40cm

The area of a trapezium with height $14 c m$ is $504 c m^{2}$ . If the parallel sides are in the ratio $4 : 5$ , find their lengths.
$30 c m, 42 c m$ .
$32 c m, 40 c m$ .
$32 c m, 42 c m$ .
$30 c m, 40 c m$ .

Area of trapezium $= \frac{1}{2}$ (sum of parallel opposite side)(height)
Let parallel side are $4 x, 5 x$
$504 = \frac{1}{2} (4 x + 5 x) (14)$
$\frac{(504) (2)}{9 (14)} = x$
$x = 8$
side of one side $= 4 (8) = 32 c m, 5 (8) = 40 c m$