The area of a triangle with vertices A -3- 0- B -7- 0- and C -8- 4- is148286

Question

Toppr Admin · Accepted Answer

The area of the -xA0-x394-ABC with vertices-xA0-A-x1-y1-3-0-B-x2-y2-7-0-xA0-amp-xA0-C-x3-y3-8-4- is-xA0-Ar-x394-ABC-12-x1-y2-x2212-y3-x2-y3-x2212-y1-x3-y1-x2212-y2-12-3-0-x2212-4-7-4-x2212-0-8-0-x2212-0- sq-units -8 sq- units-Hence- option C-

The area of a triangle with vertices A(3,0),B(7,0) and C(8,4) is148286

The area of the ΔABC with vertices A(x1,y1)=(3,0),B(x2,y2)=(7,0) & C(x3,y3)=(8,4) is Ar.ΔABC=12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=12{3(0−4)+7(4−0)+8(0−0)} sq.units =8 sq. units.Hence, option C.

The area of a triangle with vertices $A (3, 0), B (7, 0)$ and $C (8, 4)$ is
$14$
$8$
$28$
$6$