The area of parallelogram PQRS is 88 text-cm-2- A perpendicular from S is drawn to intersect PQ M- If SM-8 text-cm- then the length of PQ-

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Toppr Admin · Accepted Answer

R-E-F image-xA0-Area -ABCD- - 88 cm2Extending-xA0- it to-apos-T-apos-Hence- the area-xA0-of parallelogramwill be equal to area of rectangleSRTM-x2234- Area-88-SM-xD7-MT-8-xD7-MTMT- 11 cmalso- PQ - MT - 11 cm-

The area of parallelogram $P Q R S$ is $88 {cm}^{2}$ . A perpendicular from $S$ is drawn to intersect $P Q$ at $M$ . If $S M = 8 cm$ , then find the length of $P Q$ .

R.E.F image
Area (ABCD) = 88 $c m^{2}$
Extending it to
'T'
Hence, the area
of parallelogram
will be equal to area of rectangle
SRTM.
$∴$ $A r e a = 88 = S M \times M T = 8 \times M T$
MT= 11 cm
also, PQ = MT = 11 cm.

The area of parallelogram PQRS is 88 cm2. A perpendicular from S is drawn to intersect PQ at M. If SM=8 cm, then find the length of PQ.

R.E.F image Area (ABCD) = 88 cm2Extending it to'T'Hence, the area of parallelogramwill be equal to area of rectangleSRTM.∴ Area=88=SM×MT=8×MTMT= 11 cmalso, PQ = MT = 11 cm.

The area of parallelogram $P Q R S$ is $88 {cm}^{2}$ . A perpendicular from $S$ is drawn to intersect $P Q$ at $M$ . If $S M = 8 cm$ , then find the length of $P Q$ .

R.E.F image
Area (ABCD) = 88 $c m^{2}$
Extending it to
'T'
Hence, the area
of parallelogram
will be equal to area of rectangle
SRTM.
$∴$ $A r e a = 88 = S M \times M T = 8 \times M T$
MT= 11 cm
also, PQ = MT = 11 cm.