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Question

The area of the triangle formed by the points (a,b+c), (b,c+a) and (c,a+b) is

A

1

B

a+b+c

C

abc

D

0

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Solution

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Correct option is D. 0
Area $$\displaystyle =\frac{1}{2}\left [ a\left ( c+a-a-b \right )+b\left ( a+b-b-c \right )+c\left ( b+c-c-a \right ) \right ]=0$$

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