The arrangement of valency electrons in excited state of carbon is :
$2 s^{2} 2 p x^{1} 2 p y^{1}$
$2 s^{1} 2 p x^{1} 2 p y^{1} 2 p z^{1}$
$2 s^{2} 2 p x^{2}$
$2 s^{1} 2 p x^{2} 2 p y^{1}$

2 s^{2} 2 p x^{2}

2 s^{1} 2 p x^{2} 2 p y^{1}

2 s^{2} 2 p x^{1} 2 p y^{1}

2 s^{1} 2 p x^{1} 2 p y^{1} 2 p z^{1}

Open in App

Solution

Verified by Toppr

Ground state valency electronic configuration of carbon is $2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1}$
Excited state valency electronic configuration of carbon is $2 s^{1} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$
So answer is D.

Was this answer helpful?

Similar Questions

The arrangement of valency electrons in excited state of carbon is :

View Solution

Considering bohr's model to be valid for lithium atom, Energy associated with its valency electron can be given for various transitions. This valency electrons of 1st orbit. [Neglect energy of electrons of 1st orbit]

\begin{matrix} (P) & Energy of atom in ground state . & (1) & - 3.4 e v (q) & Energy of photon released in transition from . 2nd excited state to ground state . & (2) & - 13.6 e v (r) & Energy of 1st excited state . & (3) & 12.1 e v (s) & sonization energy of valency electron . & (4) & 13.6 e v \end{matrix}

View Solution

C4+ and C4- are highly unstable carbon states. It happens when carbon is either positively or negatively charged. But the number of valence electrons in the outer most shell is 8 and carbon has only 4. So why can’t carbon complete its valence electrons??

View Solution

Radiation with energy equal to the separation energy of an electron in

H -

atom in first excited state, is incident on a metal electrode. Work function of the metal is equal to the separation energy of an electron in

H e^{+}

ion in fourth excited state. Find the stopping potential (in V) for such arrangement ?
(Answer upto one decimal point)

View Solution

I

. The oxidation state of carbon in the compounds

{C H}_{4}, C_{2} H_{6}

and

C_{2} H_{2}

+ 4

I I

. Carbon has four valence electrons.

View Solution

The arrangement of valency electrons in excited state of carbon is :2s22px12py12s12px12py12pz12s22px22s12px22py1

Ground state valency electronic configuration of carbon is 2s22p1x2p1yExcited state valency electronic configuration of carbon is 2s12p1x2p1y2p1zSo answer is D.

The arrangement of valency electrons in excited state of carbon is :
$2 s^{2} 2 p x^{1} 2 p y^{1}$
$2 s^{1} 2 p x^{1} 2 p y^{1} 2 p z^{1}$
$2 s^{2} 2 p x^{2}$
$2 s^{1} 2 p x^{2} 2 p y^{1}$

Ground state valency electronic configuration of carbon is $2 s^{2} 2 p_{x}^{1} 2 p_{y}^{1}$
Excited state valency electronic configuration of carbon is $2 s^{1} 2 p_{x}^{1} 2 p_{y}^{1} 2 p_{z}^{1}$
So answer is D.