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Question

The average binding energy per nucleon is maximum for the nucleus

A

_{2} H^{4}

B

_{8} O^{16}

C

_{26} F e^{56}

D

_{92} U^{238}

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Solution

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Binding energy per nucleon increases with atomic number. The greater the binding energy per nucleon the more stable is the nucleus.
For $_{26} F e^{56}$ number of nucleons is $56.$
This is most stable nucleus, since maximum energy is needed to pull a nucleon away from it.

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