Question

# The average velocity of a body moving with uniform acceleration after travelling a distance of 3.06 m is 0.34 m/s. The change in velocity of the body is 0.18 m/s. During this time, its acceleration is

A
0.01 m/s2
B
0.02 m/s2
C
0.03 m/s2
D
0.04 m/s2
Solution
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#### Vavg=Dt⇒0.34=3.06t⇒t=3.060.34 = 9 secWe have, v=u+atv−u=at0.18=a×9⇒a=0.189=0.02 m/s2

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