The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is numerically equal to:

g

g2

g√2

√2g

A

g√2

B

g2

C

√2g

D

g

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Solution

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We have average velocity =g2 Since it is a free fall, average velocity, v=St=12gt2t=g2, where t is the time of descent and initial velocity is zero.

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