Question

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is numerically equal to:

Answer 1

We have average velocity $=\frac{g}{2}$
Since it is a free fall, average velocity, $v=\frac{S}{t}=\frac{\frac{1}{2}g{t}^2}{t}=\frac{g}{2}$, where $t$ is the time of descent and initial velocity is zero.