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Question

The base and top radius of a truncated cone is 1.5 m and 2 m respectively. The height of the cone is 60 m. What is the volume of a truncated cone? (Use π = 3).
  1. 545 m3
  2. 555 m3
  3. 535 m3
  4. 525 m3

A
535 m3
B
555 m3
C
525 m3
D
545 m3
Solution
Verified by Toppr

Volume of the truncated cone is V=πh3(R2+Rr+r2)

R = 1.5 m, r = 2 m, h = 60 m

V=(3×60)/(3)[1.52+1.5×2+22]

=60[2.25+3+4]

=60[9.25]

=555m3

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