The base of a parallelogram is three times its height. If the area of the parallelogram is $75$ sq cm, then its height is
$5 c m$
$5 \sqrt{2} c m$
$3 \sqrt{2} c m$
$15 c m$

Question

The base of a parallelogram is three times its height- If the area of the parallelogram is 75 sq cm- then its height is5 cmdisplaystyle 5sqrt-2-cmdisplaystyle 3sqrt-2-cm15 cm

Toppr Admin · Accepted Answer

Let the height of the parallelogram be x m-xA0-Then- base -3x-x2234- Area -b-xD7-h-x-xD7-3x-75-x21D2-3x2-75-x21D2-x2-753-x21D2-x2-25-x21D2-x-5

The base of a parallelogram is three times its height. If the area of the parallelogram is 75 sq cm, then its height is5cm5√2cm3√2cm15cm

Let the height of the parallelogram be x m. Then, base =3x.∴ Area =b×h=x×3x=75⇒3x2=75⇒x2=753⇒x2=25⇒x=5

The base of a parallelogram is three times its height. If the area of the parallelogram is $75$ sq cm, then its height is
$5 c m$
$5 \sqrt{2} c m$
$3 \sqrt{2} c m$
$15 c m$

Let the height of the parallelogram be $x$ m.
Then, base $= 3 x$ .
$∴$ Area $= b \times h = x \times 3 x = 75$
$\Rightarrow 3 x^{2} = 75$
$\Rightarrow x^{2} = \frac{75}{3}$
$\Rightarrow x^{2} = 25$
$\Rightarrow x = 5$