The binding energies of the atoms of elements $P$ and $Q$ are $E_{p}$ and $E_{Q}$ , respectively. Three atoms of element $Q$ fuse to form one atom of element $P$ . In this process, the energy released is $e$ . The correct relation between $E_{P}, E_{Q}$ and $e$ will be

Question

The binding energies of the atoms of elements

P

and

Q

are

E_{p}

and

E_{Q}

, respectively. Three atoms of element

Q

fuse to form one atom of element

P

. In this process, the energy released is

e

. The correct relation between

E_{P}, E_{Q}

and

e

will be

Toppr Admin · Accepted Answer

Binding energy of 3 Q elements will be 3EQSo- by energy conservation- binding energy of three P elements is equal to the sum of Q element-apos-s binding energy and the released energy-So- equation is-xA0-Ep-e-3EQEp-3EQ-x2212-e

The binding energies of the atoms of elements P and Q are Ep and EQ, respectively. Three atoms of element Q fuse to form one atom of element P. In this process, the energy released is e. The correct relation between EP,EQ and e will beEQ=3EP−eEP=3EQ−eEP=3EQ+eEQ=3EP+e

Binding energy of 3 Q elements will be 3EQSo, by energy conservation, binding energy of three P elements is equal to the sum of Q element's binding energy and the released energy.So, equation is Ep+e=3EQEp=3EQ−e

Binding energy of $3$ $Q$ elements will be $3 E_{Q}$
So, by energy conservation, binding energy of three $P$ elements is equal to the sum of $Q$ element's binding energy and the released energy.
So, equation is
$E_{p} + e = 3 E_{Q}$
$E_{p} = 3 E_{Q} - e$