The binding energy per nucleon - 1 - 2 - H - and - 2 - 4 - He - respectively are 1-1 MeV and 7-1 MeV- The energy released in MeV when two - 1 - 2 - H - nuclei fuse to form - 2 - 4 - He - is8-228-4244-4

Question

Toppr Admin · Accepted Answer

The chemical reaction of process is-xA0-2-xA0-21H-x27F6-42He

The binding energy per nucleon for $_{1}^{2} H$ and $_{2}^{4} H e$ respectively are $1.1$ MeV and $7.1$ MeV. The energy released in MeV when two $_{1}^{2} H$ nuclei fuse to form $_{2}^{4} H e$ is
$8.2$
$28.4$
$24$
$4.4$

The chemical reaction of process is:
$2_{1}^{2} H ⟶_{2}^{4} H e$

The binding energy per nucleon for 21H and 42He respectively are 1.1 MeV and 7.1 MeV. The energy released in MeV when two 21H nuclei fuse to form 42He is8.228.4244.4

The chemical reaction of process is: 2 21H⟶42He

The binding energy per nucleon for $_{1}^{2} H$ and $_{2}^{4} H e$ respectively are $1.1$ MeV and $7.1$ MeV. The energy released in MeV when two $_{1}^{2} H$ nuclei fuse to form $_{2}^{4} H e$ is
$8.2$
$28.4$
$24$
$4.4$

The chemical reaction of process is:
$2_{1}^{2} H ⟶_{2}^{4} H e$