The binding energy per nucleon the parent nucleus is mathrm-E-1- and that the daughter nuclei is mathrm-E-2-Thenmathrm-E-2-2mathrm-E-1-mathrm-E-1-mathrm-E-2-mathrm-E-2-mathrm-E-1-mathrm-E-1-2mathrm-E-2-

Question

Toppr Admin · Accepted Answer

After decay- the daughter nuclei will be more stable hence binding energy per nucleon will be more-xA0-than that of their parent nucleus-xA0-

The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ .Then
$E_{2} = 2 E_{1}$
$E_{1} > E_{2}$
$E_{2} > E_{1}$
$E_{1} = 2 E_{2}$

After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.

The binding energy per nucleon for the parent nucleus is E1 and that for the daughter nuclei is E2.ThenE2=2E1E1>E2E2>E1E1=2E2

After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.

The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ .Then
$E_{2} = 2 E_{1}$
$E_{1} > E_{2}$
$E_{2} > E_{1}$
$E_{1} = 2 E_{2}$