The bisector of the exterior angle A of triangle ABC intersects the side BC produced to D- Here CF is parallel to AD-dfrac -AB-AC- - dfrac -BD-CD-dfrac -AB-AC- - dfrac -CD-BD-dfrac -AB-AC- - dfrac -BC-CD-None of these

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Toppr Admin · Accepted Answer

The bisector of the exterior ∠A of △ABC intersects the side BC produced to D. Here CF is parallel to AD.ABAC=BDCDABAC=CDBDABAC=BCCDNone of these

The bisector of the exterior $∠ A$ of $△ A B C$ intersects the side $B C$ produced to $D$ . Here $C F$ is parallel to $A D$ .

$\frac{A B}{A C} = \frac{B D}{C D}$
$\frac{A B}{A C} = \frac{C D}{B D}$
$\frac{A B}{A C} = \frac{B C}{C D}$
None of these