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Question

The bisectors of any two adjacent angles intersect at 90

Solution
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Let ABCD be the parallelogram
OA and OB are the bisectors of A and B
From the figure, A+B=180o [co-interior angles]
12A+12B=90o
From AOB
ABO+BAO+OAB=180o [angle sum property]
OAB=180o(BAO+ABO)
OAB=180o90o [above proved]
OAB=90o

947167_195084_ans_286202d0344e48fca57148c036af3904.png

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