The bob of a simple pendulum of mass ′m′ is performing oscillations such that the tension in the string is equal to twice the weight of the bob while it is crossing the mean position. The tension in the string when the bob reaches extreme position is :
mg2
3mg2
mg
zero
A
mg
B
3mg2
C
zero
D
mg2
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Solution
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At bottom T=2mg T−mg=mV2R 2mg−mg=mV2R √Rg=V Applying Work Energy Theorem between pt. (1) and (2) mgR(1−cosθ)=12mV2 mgR(1−cosθ)=mRg2
here, θ is the angle made by the particle with the axis at its extreme point,
1−cosθ=12 θ=600 at, θ=600 T=mgcosθ ∴T=mg12
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