# The Boolean expression for NAND gate is -

**A**

$$Y = \overline {A + B}$$

#### Correct option is D. $$Y = \overline {A. B}$$

The Boolean algebra for $${\text{AND}}$$ gate is-

$$Y = A.B$$

So, the Boolean algebra for $${\text{NAND}}$$ gate is-

$$Y = \overline {A.B} $$