Given that,
The radius of both cylindrical vessel and cone is $$7\ cm$$.
The height of the cylindrical vessel is $$20\ cm$$ and that of the cone is $$3\ cm$$.
The cost of one litre milk is $$Rs.\ 20$$.
To find out,
The cost of filling the vessel completely with milk.
We know that,
Volume of cylinder = $$\pi r^2h$$
$$\Rightarrow \dfrac{22}{7} \times 7 \times 7 \times 20 $$
$$\Rightarrow 3080 \ \mathrm{cm}^{3} $$
We also know that,
Volume of Cone $$=\dfrac{1}{3}\pi r^{2} h $$
$$\Rightarrow \dfrac{1}{3} \times \dfrac{22}{7} \times 7 \times 7 \times 3 $$
$$\Rightarrow 154 \ \mathrm{cm}^{3} $$
Now,
Total volume of cylindrical vessel = volume of cylinder - volume of cone
$$\Rightarrow 3080-154=2926 \ \mathrm{cm}^{3}$$
$$\therefore \ $$ total milk required to completely fill the vessel $$=2.926\ l $$ $$[1l=1000 \ \mathrm{cm^3}]$$
$$\therefore \ $$The cost of filling milk $$ =2.926 \times 20=\mathrm{Rs} .\ 58.520 $$
Hence, the cost of milk required to completely fill the vessel is $$Rs. \ 58.520$$