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Chemistry

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The brown ring test for nitrates depends on:
oxidizing action of sulphuric acid.
the reduction of nitrate to nitric oxide.
reduction of ferrous sulphate to iron.
oxidation ofnitric oxide to nitrogen dioxide.

oxidation ofnitric oxide to nitrogen dioxide.

oxidizing action of sulphuric acid.

the reduction of nitrate to nitric oxide.

reduction of ferrous sulphate to iron.

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Solution

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The brown ring test for nitrates depends on the reduction of nitrate to nitric oxide.

$N O_{3}^{-} + 3 F e^{2 +} + 4 H^{+} \to 3 F e^{3 +} + N O + 2 H_{2} O$

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Similar Questions

(a) Explain with the help of a balanced equation, the brown ring test for nitric acid.

(b) Why is freshly pepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test ?

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(a) Explain with the help of a balanced equation the brown ring test for nitric acid.
(b) Why is freshly prepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test? [5 MARKS]

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Given below are word equations. Convert them into chemical equations using symbols and valencies. Balance the equations. Use appropriate signs for gases and precipitates in the reaction.
i) Zinc Sulphide

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ii) Silver nitrate solution

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Sodium chloride solution

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F e^{2 +}

ions react with nitric oxide formed from reduction of nitrate and yields a brown coloured complex of _________ .

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Why is freshly prepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test?

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The brown ring test for nitrates depends on:oxidizing action of sulphuric acid.the reduction of nitrate to nitric oxide.reduction of ferrous sulphate to iron.oxidation ofnitric oxide to nitrogen dioxide.

The brown ring test for nitrates depends on the reduction of nitrate to nitric oxide.NO3−+3Fe2++4H+→3Fe3++NO+2H2O

The brown ring test for nitrates depends on:
oxidizing action of sulphuric acid.
the reduction of nitrate to nitric oxide.
reduction of ferrous sulphate to iron.
oxidation ofnitric oxide to nitrogen dioxide.

The brown ring test for nitrates depends on the reduction of nitrate to nitric oxide.

$N O_{3}^{-} + 3 F e^{2 +} + 4 H^{+} \to 3 F e^{3 +} + N O + 2 H_{2} O$