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Question

The calculated spin only magnetic moment of $$Cr^{2+}$$ ion is

A
$$5.92 BM$$
B
$$4.90 BM$$
C
$$2.84 BM$$
D
$$3.87 BM$$
Solution
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Correct option is A. $$4.90 BM$$
Electronic configuration of the ion:

$$Cr^{2+} \Rightarrow [Ar] 4s^0 3d^4$$

$$n=4$$
Spin only magnetic moment $$\Rightarrow \sqrt {n(n+2)} = \sqrt {4 \times (4+2)}=4.9 BM$$
Option A is correct.

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