The calculated spin only magnetic moment of $$Cr^{2+}$$ ion is
Correct option is A. $$4.90 BM$$
Electronic configuration of the ion:
$$Cr^{2+} \Rightarrow [Ar] 4s^0 3d^4$$
$$n=4$$
Spin only magnetic moment $$\Rightarrow \sqrt {n(n+2)} = \sqrt {4 \times (4+2)}=4.9 BM$$
Option A is correct.