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Question

The capacitance of a condenser is $20 μ F$ and it is charged to a potential of 2000 V. The energy stored in it will be :
80 J
zero
40 J
120 J

A

80 J

B

zero

C

120 J

D

40 J

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Solution

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Given
$C = 20 μ F, V = 2000 V$
Energy stored in the condenser is $U = \frac{1}{2} C V^{2} = \frac{1}{2} \times 20 \times 10^{- 6} \times (2000)^{2} = 40 J$

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