The capacitance of a parallel plate capacitor is $C_{0}$ when the plates have air between them. This region is now filled with a dielectric slab of dielectric constant $K$ and capacitor is connected with a battery of emf $E$ and zero internal resistance. Now slab is taken out, then during removal of slab:

$1.)$ Charge $E C_{0} (K - 1)$ flows through the cell.

$2.)$ Energy $E^{2} C_{0} (K - 1)$ is absorbed by cell.

$3.)$ The energy stored in the capacitor is reduced by $E^{2} C_{0} (K - 1)$ .

$4.)$ The external agent has to do $E^{2} C_{0} (K - 1)$ amount of work to take out the slab.

Select the correct phenomenon happening during the process:

Question

The capacitance of a parallel plate capacitor is

C_{0}

when the plates have air between them. This region is now filled with a dielectric slab of dielectric constant

K

and capacitor is connected with a battery of emf

E

and zero internal resistance. Now slab is taken out, then during removal of slab:

1.)

Charge

E C_{0} (K - 1)

flows through the cell.

2.)

Energy

E^{2} C_{0} (K - 1)

is absorbed by cell.

3.)

The energy stored in the capacitor is reduced by

E^{2} C_{0} (K - 1)

.

4.)

The external agent has to do

E^{2} C_{0} (K - 1)

amount of work to take out the slab.

Select the correct phenomenon happening during the process:

Toppr Admin · Accepted Answer