The capacity of a condenser is 20mu F displaystyle and the potential is 20 V- The energy released an discharging it fully will bedisplaystyle 8times - 10 - -3 -Jdisplaystyle 4times - 10 - -3 -Jdisplaystyle 2times - 10 - -3 -Jdisplaystyle 10times - 10 - -3 -J

Question

The capacity of a condenser is 20mu F displaystyle  and the potential is 20 V- The energy released an discharging it fully will bedisplaystyle 8times - 10 - -3 -Jdisplaystyle 4times - 10 - -3 -Jdisplaystyle 2times - 10 - -3 -Jdisplaystyle 10times - 10 - -3 -J

Toppr Admin · Accepted Answer

The energy released on discharging will beU-12CV2-12-xD7-20-xD7-10-x2212-6-xD7-20-xD7-20-4-xD7-10-x2212-3J

The capacity of a condenser is 20 $μ F$ and the potential is 20 V. The energy released an discharging it fully will be
$8 \times 10^{- 3} J$
$4 \times 10^{- 3} J$
$2 \times 10^{- 3} J$
$10 \times 10^{- 3} J$

The energy released on discharging will be
$U = \frac{1}{2} C V^{2}$
$= \frac{1}{2} \times 20 \times 10^{- 6} \times 20 \times 20 = 4 \times 10^{- 3} J$

The capacity of a condenser is 20μF and the potential is 20 V. The energy released an discharging it fully will be8×10−3J4×10−3J2×10−3J10×10−3J

The energy released on discharging will beU=12CV2=12×20×10−6×20×20=4×10−3J

The capacity of a condenser is 20 $μ F$ and the potential is 20 V. The energy released an discharging it fully will be
$8 \times 10^{- 3} J$
$4 \times 10^{- 3} J$
$2 \times 10^{- 3} J$
$10 \times 10^{- 3} J$

The energy released on discharging will be
$U = \frac{1}{2} C V^{2}$
$= \frac{1}{2} \times 20 \times 10^{- 6} \times 20 \times 20 = 4 \times 10^{- 3} J$