The capacity of a parallel plate air condenser is $2 μ F$ . If a dielectric of dielectric constant $4$ is introduced between the plates, its new capacity is:
$0.5 μ F$
$6 μ F$
$1.5 μ F$
$8 μ F$

Question

The capacity of a parallel plate air condenser is 2 mu F- If a dielectric of dielectric constant 4 is introduced between the plates- its new capacity is-0-5 mu F6 mu F1-5 mu F8 mu F

Toppr Admin · Accepted Answer

We know C-x3F5-0AdWhen dielectric is added-C-x2032-K-x3F5-0Ad-4-xD7-2-xA0-x3BC-F-8-x3BC-F

The capacity of a parallel plate air condenser is 2 μF. If a dielectric of dielectric constant 4 is introduced between the plates, its new capacity is:0.5 μF6 μF1.5 μF8 μF

We know C=ϵ0AdWhen dielectric is added:C′=Kϵ0Ad=4×2 μF=8μF

The capacity of a parallel plate air condenser is $2 μ F$ . If a dielectric of dielectric constant $4$ is introduced between the plates, its new capacity is:
$0.5 μ F$
$6 μ F$
$1.5 μ F$
$8 μ F$

We know $C = \frac{ϵ_{0} A}{d}$
When dielectric is added:
$C^{'} = \frac{K ϵ_{0} A}{d}$ $= 4 \times 2 μ F$ $= 8 μ F$