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Question

The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2μF. The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is
  1. 11.2μF
  2. 19.2μF
  3. 22.4μF
  4. 15.6μF

A
11.2μF
B
22.4μF
C
19.2μF
D
15.6μF
Solution
Verified by Toppr

Initial capacitance C=2uF=ε0Ad
New capacitance C=Kε0Ad=2.8×ε0A(d/2)=5.6ε0Ad
C=5.6×2=11.2μF

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