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Question

The capacity of a parallel plate condenser is 5μF.When a glass plate is placed between the plates of the condenser,its potential difference reduces to 1/8 of original value.The magnitude of relative dielectric constant of glass is
  1. 2
  2. 6
  3. 7
  4. 8

A
2
B
7
C
8
D
6
Solution
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The correct option is D 8
Potential of a capacitor without dielectric, V=QC=QdAε0 where
Q is the charge on the capacitor
d is the plate distance
A is the area of plates
ε0 is permeability of free space
After insertion of dielectric,potential becomes:
V=QC=QdkAε0 where k is dielectric constant.
since, V=V8
QdkAε0=Qd8Aε0
k=8

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