The capacity of a parallel plate condenser with air medium is 60μF having distance of separation d . If the space between the plates is filled with two slabs each of thickness d/2 and dielectric constants 4 and 8, the effective capacity becomes :
160μ F
320μ F
360μ F
640μ F
A
160μ F
B
640μ F
C
320μ F
D
360μ F
Open in App
Solution
Verified by Toppr
Given initial capacitance C=60μF ⇒60μF=ε0Ad When the distance is filled with materials with different dielectric medium we have two capacitance C1=k1ε0A(d2) and C2=k2ε0A(d2) in series. C1=4×60×2μFC2=8×60×2μF C1=480μF and C2=960μF We know, when capacitors are in series: 1ceff=1c1+1c2 ∴1ceff=1480+1960⇒Ceff=320μF.
Was this answer helpful?
0
Similar Questions
Q1
The capacity of a parallel plate condenser with air medium is 60μF having distance of separation d . If the space between the plates is filled with two slabs each of thickness d/2 and dielectric constants 4 and 8, the effective capacity becomes :
View Solution
Q2
A parallel plate condenser of capacity 5 μ F is kept connected to a battery of emf 10 V. If the space between the plates is filled with a medium of dielectric constant 12, then the additional charge taken from the battery is?
View Solution
Q3
The capacity of a parallel plate condenser with air medium is C . If half of the space between the plates is filled with a slab of dielectric constant K as shown in the figure, then the capacity becomes :
View Solution
Q4
A parallel plate condenser initially has air as a medium between the plates. If a slab of dielectric constant 5 having thickness half the distance of separation between the plates is introduced, the percentage increase in its capacity will be ___
View Solution
Q5
The capacity of a parallel plate condenser without any dielectric is C. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant 3, the capacity of the condenser becomes: