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Question

The capacity of a parallel plate condenser with air medium is 60μF having distance of separation d . If the space between the plates is filled with two slabs each of thickness d/2 and dielectric constants 4 and 8, the effective capacity becomes :


  1. 160μ F
  2. 320μ F
  3. 360μ F
  4. 640μ F

A
160μ F
B
640μ F
C
320μ F
D
360μ F
Solution
Verified by Toppr

Given initial capacitance
C=60μF
60μF=ε0Ad
When the distance is filled with materials with different dielectric medium we have two capacitance
C1=k1ε0A(d2) and C2=k2ε0A(d2) in series.
C1=4×60×2μF C2=8×60×2μF
C1=480μF and C2=960μF
We know, when capacitors are in series:
1ceff=1c1+1c2
1ceff=1480+1960Ceff=320μF.

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