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Question

The change in internal energy of the methanol is
  1. 9.6×105J
  2. 6.89×104J
  3. 7.14×105J
  4. 6.86×105J

A
7.14×105J
B
9.6×105J
C
6.89×104J
D
6.86×105J
Solution
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ΔQ=mCpΔT=ρVgasCPΔT

From given data :
ρ=791 kg/m3,

ΔT=30C

V=1.2×102 m3

CP=2.51×103 J(kgK)1

ΔQ=7.14×105 J

work done will be W=PΔV=PV(1+γΔT)

γ=1.2×103

W=3.62×102

From First law of thermodynamics:

ΔU=ΔQW=7.14×105J

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