The change in potential energy- when a body of mass m is raised to a height nR from the earth-s surface is -R- radius of earth-displaystyle nmgRdisplaystyle mgR left - frac -n-n-1-right -displaystyle mgR left - frac -n-n-1-right -displaystyle mgR left - frac -n-2-n-2-1-right -

Question

Toppr Admin · Accepted Answer

-x25B3-U-Uf-x2212-Ui-x2212-GMmnR-h-x2212-x2212-GMmR-

The change in potential energy, when a body of mass $m$ is raised to a height $n R$ from the earth's surface is $(R =$ radius of earth $)$
$n m g R$
$m g R (\frac{n}{n - 1})$
$m g R (\frac{n}{n + 1})$
$m g R (\frac{n^{2}}{n^{2} + 1})$

$△ U = U_{f} - U_{i} = - \frac{G M m}{n R + h} - (- \frac{G M m}{R})$

The change in potential energy, when a body of mass m is raised to a height nR from the earth's surface is (R= radius of earth)nmgRmgR(nn−1)mgR(nn+1)mgR(n2n2+1)

△U=Uf−Ui=−GMmnR+h−(−GMmR)

The change in potential energy, when a body of mass $m$ is raised to a height $n R$ from the earth's surface is $(R =$ radius of earth $)$
$n m g R$
$m g R (\frac{n}{n - 1})$
$m g R (\frac{n}{n + 1})$
$m g R (\frac{n^{2}}{n^{2} + 1})$

$△ U = U_{f} - U_{i} = - \frac{G M m}{n R + h} - (- \frac{G M m}{R})$