The change in the value of g at a height h about the surface of the earth is the same as at a depth d below the surface of earth. When both d and h are much smaller than the radius of earth, then which one of the following is correct?
d=3h2
d=h
d=2h
d=h2
A
d=h
B
d=2h
C
d=3h2
D
d=h2
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Solution
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Acceleration due to gravity at a height h, g′h=g(1−2hR) Acceleration due to gravity at a depth d, g′d=g(1−dR) ∴g(1−2hR)=g(1−dR) or 2hR=dR or d=2h.
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