The circuit below shows three identical resistors labeled $1,2$ and $3$.
The reading on the ammeter is $12.0A$. How much current flows in each resistor?

Let    $R_1=R_2=R_3=R$       (as resistors are identical) ,

therefore equivalent resistance ,

         $\frac{1}{R^{\prime }}=\frac{1}{R}+\frac{1}{R}+\frac{1}{R}$ ,

   or   $R^{\prime }=R/3$ ,

given total current in the circuit    $I=12.0A$ ,

therefore     voltage  $V=I{R}^{\prime }=12.0\times (R/3)=4.0R$ ,

as the resistors are in parallel combination so voltage across them will be same that is $V=IR$ ,

  now current through $R_1$ ,

                                   $I_1=V/R=4.0R/R=4.0A$ ,

since the resistors are equal therefore this will also be the current through $R_2$  and $R_3$ .