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Question

The circumcenter of the triangle with vertices at (0,0), (8,0) and (0,-6) is at
(3,4)
(2,3)
(4,-3)
(4,3)

A

(3,4)

B

(2,3)

C

(4,-3)

D

(4,3)

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Solution

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Plot the points The circumcenter of triangle OAB is the midpoint of AB, i.e.
$(\frac{8 + 0}{2}, \frac{0 - 6}{2}) = (4, - 3)$

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