Question

The circumference of the base of a 12 m high conical tent is 66 m. Find the volume of the air contained in it.

Answer 1

Circumference of the base $=66\text{m}$

Height of the tent $=12\text{m}$

Circumference of the circle $=2\pi r$

$66=2\ast \frac{22}{7}\ast r$

$\frac{66\ast 7}{2\ast 22}=r$

$r=10.5\text{m}$

Volume of the cone $=\frac{1}{3}\pi r^{2}h$

$=\frac{1}{3}\ast \frac{22}{7}\ast 10.5\ast 10.5\ast 12$

$=1386{\text{m}}^3$

So, the volume of the air contained in it is $=1386{\text{m}}^3$