The circumference of the base of cylindrical water tank is 264 cm and its height is 12 cm. Find the cuved surface area of the cylindrical water tank . (Assume $π = 22 / 7$ ).

Question

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Answer 1

Circumference of cylinder is $C = 2 π r$

It is given that the circumference of water tank is $264$ cm, therefore,

$C = 2 π r \Rightarrow 264 = 2 π r \Rightarrow r = \frac{2 6 4}{2 π} = \frac{1 3 2}{π}$

Now, curved surface area of cylinder is $A = 2 π r h$

Here, the radius is $\frac{1 3 2}{π}$ cm and height is $12$ cm.

Thus,

$A = 2 π r h = 2 π \times \frac{1 3 2}{π} \times 12 = 2 \times 132 \times 12 = 3168$ cm $^{2}$

Hence, the curved surface area of cylindrical water tank is $3168$ cm $^{2}$ .

Answer 2

Circumference of cylinder is

C = 2 π r

It is given that the circumference of water tank is

264

cm, therefore,

C = 2 π r \Rightarrow 264 = 2 π r \Rightarrow r = \frac{2 6 4}{2 π} = \frac{1 3 2}{π}

Now, curved surface area of cylinder is

A = 2 π r h

Here, the radius is

\frac{1 3 2}{π}

cm and height is

12

cm.

Thus,

A = 2 π r h = 2 π \times \frac{1 3 2}{π} \times 12 = 2 \times 132 \times 12 = 3168

cm

^{2}

Hence, the curved surface area of cylindrical water tank is

3168

cm

^{2}

.