Question

The circumference of the base of cylindrical water tank is 264 cm and its height is 12 cm. Find the cuved surface area of the cylindrical water tank . (Assume $\pi =22/7$).

• A. $3168{cm}^2$
• B. $3168m^2$
• C. 3168 $m^2$
• D. $3208{cm}^2$

Answer 1

Answer: (A)

The correct option is C $3168{cm}^2$

Circumference of cylinder is $C=2\pi r$

It is given that the circumference of water tank is $264$ cm, therefore,

$C=2\pi r\Rightarrow 264=2\pi r\Rightarrow r=\frac{264}{2\pi }=\frac{132}{\pi }$

Now, curved surface area of cylinder is $A=2\pi rh$

Here, the radius is $\frac{132}{\pi }$ cm and height is $12$ cm.

Thus,

$A=2\pi rh=2\pi \times \frac{132}{\pi }\times 12=2\times 132\times 12=3168$ cm${}^2$

Hence, the curved surface area of cylindrical water tank is $3168$ cm${}^2$.