The circumference of the base of the of a cylinder is 12 m and its height is $π$ meters. The volume of the cylinder is
$28 m^{3}$
$38 m^{3}$
$36 m^{3}$
$22 m^{3}$

Question

The circumference of the base of the of a cylinder is 12 m and its height is $π$ meters. The volume of the cylinder is
$28 m^{3}$
$38 m^{3}$
$36 m^{3}$
$22 m^{3}$

Toppr Admin · Accepted Answer

Circumference-12m and height -h-x3C0-m Therefore2-x3C0-r-12 or-xA0-r-122-x3C0-6-x3C0-Now V-x3C0-r2h-x3C0-xD7-6-x3C0-2-xD7-x3C0-x3C0-xD7-36-xD7-x3C0-x3C0-xD7-x3C0-36m3

The circumference of the base of the of a cylinder is 12 m and its height is π meters. The volume of the cylinder is28m338m336m322m3

Circumference=12m and height (h)=πm Therefore2πr=12 or r=122π=6πNow V=πr2h=π×(6π)2×π=π×36×ππ×π=36m3

The circumference of the base of the of a cylinder is 12 m and its height is $π$ meters. The volume of the cylinder is
$28 m^{3}$
$38 m^{3}$
$36 m^{3}$
$22 m^{3}$

Circumference=12m and height (h)= $π m$ Therefore
$2 π r = 12$ or $r = \frac{12}{2 π} = \frac{6}{π}$
Now V= $π r^{2} h$
= $π \times {(\frac{6}{π})}^{2} \times π$
= $\frac{π \times 36 \times π}{π \times π}$
=36 $m^{3}$