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Question

The combustion of a hydrocarbon A gives 0.66 g of carbon dixode and 0.36 g of water. The empirical formula of the hydrocarbon is:
  1. C3H10
  2. C3H8
  3. C3H4
  4. C6H8

A
C6H8
B
C3H8
C
C3H10
D
C3H4
Solution
Verified by Toppr

44gofCO21molofcarbon

0.66gofCO20.66/44=0.015molC

18gofH2O2molofHydrogen

0.36gofH2O218×0.36=0.04molH

molarratioofC:His0.015:0.04
C:H=1:8/3=3:8Empiricalformula=C3H8

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