The correct sequence of decreasing number of pi-bonds in the structures of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is:

$H_{2} S O_{4} > H_{2} S_{2} O_{7} > H_{2} S O_{3}$
$H_{2} S O_{3} > H_{2} S O_{4} > H_{2} S_{2} O_{7}$
$H_{2} S_{2} O_{7} > H_{2} S O_{3} > H_{2} S O_{4}$
$H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$

Question

Toppr Admin · Accepted Answer

-xA0-The correct sequence of decreasing number of pi-bonds is H2S2O7-4-gt-H2SO4-2-gt-H2SO3-1- The numbers in bracket indicate the number of pi bonds-

The correct sequence of decreasing number of pi-bonds in the structures of H2SO3,H2SO4 and H2S2O7 is: H2SO4>H2S2O7>H2SO3H2SO3>H2SO4>H2S2O7H2S2O7>H2SO3>H2SO4H2S2O7>H2SO4>H2SO3