The construction of a triangle ABC- given that BC - 6 cm- B - 45 -circ- is not possible when difference of AB and AC is equal to-5-2 cm6-9 cm4-0 cm5-0 cm

Question

Toppr Admin · Accepted Answer

According to the theorem of inequalities- the sum of any two sides of the triangle is greater than the third side-Therefore-xA0-AC-BC-gt-AB-x21D2-BC-gt-AB-x2212-ACTherefore- only the first option that is 6-9 cm does not satisfy the above equation- Rest all the options satisfy the equation-

The construction of a triangle ABC, given that BC= 6 cm, B= 45∘ is not possible when difference of AB and AC is equal to:5.2 cm6.9 cm4.0 cm5.0 cm

According to the theorem of inequalities, the sum of any two sides of the triangle is greater than the third side.Therefore, AC+BC>AB⇒BC>AB−ACTherefore, only the first option that is 6.9 cm does not satisfy the above equation. Rest all the options satisfy the equation.

The construction of a triangle $A B C$ , given that $B C =$ $6$ cm, $B =$ $45^{\circ}$ is not possible when difference of $A B$ and $A C$ is equal to:
$5.2$ cm
$6.9$ cm
$4.0$ cm
$5.0$ cm