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Magnetic Properties

Question

The correct order of spin-only magnetic moments among the following is:

(Atomic number: $M n = 25, C o = 27, N i = 28, Z n = 30)$ .

$[Z n C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -}$
$[C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}$
$[N i C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}$
$[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}$

A

[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}

B

[Z n C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -}

C

[C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}

D

[N i C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [M n C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}

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Solution

Verified by Toppr

The complex having higher number of unpaired electrons will have higher value of spin-only magnetic moment.

The correct order of spin-only magnetic moments is $[M n C l_{4}]^{2 -} > [C o C l_{4}]^{2 -} > [N i C l_{4}]^{2 -} > [Z n C l_{4}]^{2 -}$ .

In these complexes, the central metal ion is in $+ 2$ oxidation state.

$Z n^{2 +}$ has $3 d^{10}$ outer electronic configuration with $0$ unpaired electrons.

$N i^{2 +}$ has $3 d^{8}$ outer electronic configuration with $2$ unpaired electrons.

$C o^{2 +}$ has $3 d^{7}$ outer electronic configuration with $3$ unpaired electrons.

$M n^{2 +}$ has $3 d^{5}$ outer electronic configuration with $5$ unpaired electrons.

Hence, the correct option is D.

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