The correct relation between K-p and K-c the given reaction is-H-2-g- - l-1-g- rightleftharpoons 2Hl-g-dfrac-K-p-RT- - K-cK-p - K-c-RT-2-K-p - K-c-RT-2K-p - K-c

Question

Toppr Admin · Accepted Answer

The correct option is B Kp-KcGenerally Kp-Kc-RT-x394-n-x394-n- no- of mole of products - no- of moles of reactants-xA0-Here no- of product moles -2no- of reactant moles -2So -x394-n-2-x2212-2-0Kp-Kc-RT-0-KcSo for this reaction- Kp-Kc

The correct relation between $K_{p}$ and $K_{c}$ for the given reaction is:
$H_{2} (g) + l_{1} (g) ⇌ 2 H l (g)$
$\frac{K_{p}}{R T} = K_{c}$
$K_{p} = K_{c} (R T)^{- 2}$
$K_{p} = K_{c} (R T)^{2}$
$K_{p} = K_{c}$

The correct option is B $K_{p} = K_{c}$
Generally K $_{p} = K_{c} (R T)^{Δ n}$
$Δ n =$ no. of mole of products - no. of moles of reactants.
Here no. of product moles $= 2$
no. of reactant moles $= 2$
So $Δ n = 2 - 2 = 0$
$K_{p} = K_{c} (R T)^{0} = K_{c}$
So for this reaction, $K_{p} = K_{c}$

The correct relation between Kp and Kc for the given reaction is:H2(g)+l1(g)⇌2Hl(g)KpRT=KcKp=Kc(RT)−2Kp=Kc(RT)2Kp=Kc

The correct option is B Kp=KcGenerally Kp=Kc(RT)ΔnΔn= no. of mole of products - no. of moles of reactants. Here no. of product moles =2no. of reactant moles =2So Δn=2−2=0Kp=Kc(RT)0=KcSo for this reaction, Kp=Kc

The correct relation between $K_{p}$ and $K_{c}$ for the given reaction is:
$H_{2} (g) + l_{1} (g) ⇌ 2 H l (g)$
$\frac{K_{p}}{R T} = K_{c}$
$K_{p} = K_{c} (R T)^{- 2}$
$K_{p} = K_{c} (R T)^{2}$
$K_{p} = K_{c}$

The correct option is B $K_{p} = K_{c}$
Generally K $_{p} = K_{c} (R T)^{Δ n}$
$Δ n =$ no. of mole of products - no. of moles of reactants.
Here no. of product moles $= 2$
no. of reactant moles $= 2$
So $Δ n = 2 - 2 = 0$
$K_{p} = K_{c} (R T)^{0} = K_{c}$
So for this reaction, $K_{p} = K_{c}$