The correct of four quantum numbers the valence electrons of rubidium atom -Z-37- is- 5- 1- 1- -displaystyle frac-1-2- 5- 0- 1- -displaystyle frac-1-2- 5- 0- 0- -displaystyle frac-1-2- 5- 1- 0- -displaystyle frac-1-2-

Question

Toppr Admin · Accepted Answer

The electronic configuration of rubidium (Z=37) is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 5 s^{1}$ .

The valence electron is present in $5 s^{1}$ subshell.

Hence, the set of quantum numbers are $n = 5, l = 0, m = 0$ and $s = + \frac{1}{2}$ .

Hence, the correct option is $C$

The correct set of four quantum numbers for the valence electrons of rubidium atom [Z=37] is:5,1,1,+125,0,1,+125,0,0,+125,1,0,+12

The electronic configuration of rubidium (Z=37) is 1s22s22p63s23p63d104s24p65s1.The valence electron is present in 5s1 subshell. Hence, the set of quantum numbers are n=5,l=0,m=0 and s=+12.Hence, the correct option is C

The correct set of four quantum numbers for the valence electrons of rubidium atom $[Z = 37]$ is:
$5, 1, 1, + \frac{1}{2}$
$5, 0, 1, + \frac{1}{2}$
$5, 0, 0, + \frac{1}{2}$
$5, 1, 0, + \frac{1}{2}$