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>>Nuclei
>>First Order Radioactive Decay
>> $The counting rate of disintegration of r$

Question

The counting rate of disintegration of radioactive source at $t = 0$ second was $1600$ counts per second and at $t = 8$ seconds was $100$ counts per second. The counting rate observed as counts per seconds, at $t = 6$ second would have been

A

$100$

B

$200$

C

$300$

D

$400$

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Updated on : 2022-09-05

Solution

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Correct option is B)

In $8 s e c$ count is $100$
So, $2^{n} = \frac{1 6 0 0}{1 0 0}$
$n = 4$ , so in 8 sec there are four half lifes,half life is $2 s e c$
In $6 s e c$ there are 3 half life, count after $6 s e c =$ $\frac{1 6 0 0}{2 ^{3}}$ $= 200$

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