0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The counting rate of disintegration of radioactive source at t=0 second was 1600 counts per second and at t=8 seconds was 100 counts per second. The counting rate observed as counts per seconds, at t=6 second would have been
  1. 100
  2. 200
  3. 300
  4. 400

A
200
B
400
C
100
D
300
Solution
Verified by Toppr

In 8 sec count is 100
So, 2n=1600100
n=4, so in 8 sec there are four half lifes,half life is 2 sec
In 6 sec there are 3 half life, count after 6 sec= 160023=200

Was this answer helpful?
1
Similar Questions
Q1
The counting rate of disintegration of radioactive source at t=0 second was 1600 counts per second and at t=8 seconds was 100 counts per second. The counting rate observed as counts per seconds, at t=6 second would have been
View Solution
Q2
The counting rate observed from a radioactive source at t=0 second was 1600 counts per second and at t=8 seconds it was 100 counts per second. The counting rate observed as counts per second at t=6 seconds, will be
View Solution
Q3
The counting rate observed from a radioactive source at t = 0 second was 1600 counts per second and at t = 8 seconds it was 100 counts per second. The counting rate observed as counts per second at t = 6 seconds will be
View Solution
Q4
Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t=0 it was 1600 counts per second and t=8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t=6 seconds is close to
View Solution
Q5
The count rate observed from a radioactive source at t second was N0 and at 4t second it was N016. The count rate observed at (112)t second will be
View Solution