The critical angle for light going from a medium in which wavelength is 4000A∘ to medium in which its wavelength is 6000A∘ is :
30∘
45∘
60∘
sin−1(23)
A
sin−1(23)
B
30∘
C
60∘
D
45∘
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Solution
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Wavelength in medium =wavelengthμ
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