The current through the 5Omega resistor is-

Question

Toppr Admin · Accepted Answer

Correct option is A- -2-ALet the current in -5-Omega- be -i-According to Kirchhoff Voltage Law-In -1-st- loop-10-5-i-0-In -2-nd- loop-10-5-i-0-From the both equations-160-Value of -i- comes to be -dfrac-10-2-5A-

The current through the $$5\Omega$$ resistor is?

Correct option is A. $$2$$A
Let the current in $$5\Omega$$ be $$i$$,

According to Kirchhoff Voltage Law,
In $$1^{st}$$ loop,

$$10-5_i=0$$

In $$2^{nd}$$ loop,

$$10-5_i=0$$

From the both equations,
Value of $$i$$ comes to be $$=\dfrac{10}{2}=5A$$

The current through the $$5\Omega$$ resistor is?

Correct option is A. $$2$$ALet the current in $$5\Omega$$ be $$i$$,According to Kirchhoff Voltage Law,In $$1^{st}$$ loop,$$10-5_i=0$$In $$2^{nd}$$ loop,$$10-5_i=0$$From the both equations, Value of $$i$$ comes to be $$=\dfrac{10}{2}=5A$$

Correct option is A. $$2$$A
Let the current in $$5\Omega$$ be $$i$$,

According to Kirchhoff Voltage Law,
In $$1^{st}$$ loop,

$$10-5_i=0$$

In $$2^{nd}$$ loop,

$$10-5_i=0$$

From the both equations,
Value of $$i$$ comes to be $$=\dfrac{10}{2}=5A$$