The deBroglie wavelength associated with a particle of mass m, moving with a velocity ′v′ and energy E is given by

hmv2

mvh2

h√2mE

√2mE/h

A

√2mE/h

B

mvh2

C

h√2mE

D

hmv2

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Solution

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We know, 12mv2=E mv=√2Em so debroglie wavelength (λ)=hmv =h√2Em

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