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Question

# The deBroglie wavelength associated with a particle of mass m, moving with a velocity ′v ′ and energy E is given byhmv2mvh2h√2mE√2mE/h

A
2mE/h
B
mvh2
C
h2mE
D
hmv2
Solution
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#### We know,12mv2=Emv=√2Emso debroglie wavelength (λ)=hmv=h√2Em

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