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Question

The decreasing basic character of the following is:
(I) PhO (II) CH3S (III) OH (IV) MeO

  1. I>II>III>IV
  2. III>IV>II>I
  3. IV>III>II>I
  4. I>II>IV>III

A
III>IV>II>I
B
IV>III>II>I
C
I>II>III>IV
D
I>II>IV>III
Solution
Verified by Toppr

The increasing acidic character is PhOH>CH3SH>MeOH>H2O.
Phenols are most acidic (due to resonance stabilization in phenoxide ion) and water is least acidic.
The decreasing basic character is PhO<CH3S<MeO<OH. As the acidic character increases, the basic character of conjugate base decreases. Since phenols are most acidic, phenoxide ions are least basic.

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