0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The denominator of a rational number is greater than its numerator by 7. If the numerator is increased by 17 and the denominator decreased by 6, the new number becomes 2. Find the original number.

Solution
Verified by Toppr

Let the fraction be pq
So q=p+7
p+17q6=2
p+17p+76=2
p+17p+1=2
p+17=2p+2
p=15
q=15+7=22
So pq=1522.

1208501_1454178_ans_bab6cc827d1a4f60a18cc8f3160cbefe.jpg

Was this answer helpful?
6
Similar Questions
Q1
The denominator of a rational number is greater than its numerator by 7. If the numerator is increased by 17 and the denominator decreased by 6, the new number becomes 2. Find the original number.
View Solution
Q2

The denominator of a rational number is greater than its numerator by 3. If the numerator is increased by 7 and the denominator is decreased by 1, then the new number becomes 32. Find the original number.


View Solution
Q3
The denominator of a rational number is greater than its numerator by 3. If the numeratoris increased by 7 and the denominator is decreased by 1, the new number becomes 32.Find the original number.
View Solution
Q4
The denominator of a rational number is greater than its numerator by 5. If the numerator is increased by 6 and denominator is decreased by 3, the number becomes 53. Find the original number.
View Solution
Q5

The denominator of a rational number is greater than its numerator by 3. If the numerator is increased by 7 and the denominator is decreased by 1, the number becomes 32. The original number is:


View Solution